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Uniqueness of Laplace transform
Statement: Let $L_f(t) = \int_0^\infty f(x)e^{-tx} dx$. Then if $f(x) = o(e^{ax})$ for some $a > 0$, $L_f = L_g$ implies $f = g$. Proof: By linearity of the integral, this is equivalent to showing $L_f = 0$ implies $f = … Continue reading
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