Analysis exercises

1. Prove that if fn converges to 0 in L2 and fnL21 for each n, then fn(x)n converges pointwise to 0 a.e.

Proof: Pick ϵ>0. Let An={x:|fn(x)n|ϵ}. Then we have

1n2|fnn|2An|fnn|2Anϵ2=ϵ2m(An)

so that m(An)1ϵ2n2. Then An< and so by Borel-Cantelli, lim supAn=0, so for almost all x, lim sup|fn(x)/n|<ϵ. Since ϵ was arbitrary, we’re done.

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