Monthly Archives: July 2018

Fourier transform

Statement. $F[e^{-\pi x^2}] = e^{-\pi x^2}$ Proof. $$ \begin{eqnarray} F[e^{-\pi x^2}](s) &=& \int_{\Bbb R} e^{-\pi x^2} e^{-2\pi i sx} dx \\ &=& \int_{\Bbb R} e^{-\pi x^2 -2\pi i sx} dx \\ &=& e^{\pi (is)^2} \int_{\Bbb R} e^{-\pi x^2 -2\pi i sx – … Continue reading

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